Mikhael Bogdanov 6bf70a5dd2 Properly find invoke method on default lambda inlining ...

In general case parameter type could differ from actual default lambda type.
  E.g.: fun inlineFun(s: (Child) -> Base = { a: Base -> a as Child}),
  where type of default lambda is '(Base) -> Child'.
  In such case we should find somehow actual invoke method in bytecode knowing
  only name, number of parameters and that's actual invoke is non-synthetic
  regardless of bridge one.

  #KT-21946 Fixed

2019-01-02 12:37:06 +01:00

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