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project_euler/e_49.py
Julien Lengrand-Lambert 087f7a5ac6 Finishes problem 49
2014-05-22 23:01:22 +02:00

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2.9 KiB
Python

#!/usr/bin/env python
'''
Created on 10 feb. 2012
@author: Julien Lengrand-Lambert
DESCRIPTION: Solves problem 49 of Project Euler
The arithmetic sequence, 1487, 4817, 8147, in which each of the terms increases by 3330, is unusual in two ways:
(i) each of the three terms are prime, and, (ii) each of the 4-digit numbers are permutations of one another.
There are no arithmetic sequences made up of three 1-, 2-, or 3-digit primes, exhibiting this property,
but there is one other 4-digit increasing sequence.
What 12-digit number do you form by concatenating the three terms in this sequence?
'''
import pickle
import itertools
# list of primes up to one million.
plist = pickle.load(open("primes_list.dup", "rb"))
def fourLengthPrime():
"""
Returns the list of all prime numbers of length 4
"""
return[val for val in plist if len(str(val)) == 4]
def isPrime(val):
"""
Returns True if the number is prime
"""
return (val in plist)
def all_permutations(seq):
"""permutate a sequence and return a list of the permutations"""
if not seq:
return [seq] # is an empty sequence
else:
temp = []
for k in range(len(seq)):
part = seq[:k] + seq[k+1:]
for m in all_permutations(part):
temp.append(seq[k:k+1] + m)
return temp
def getPrimesPermutations(primes, length):
"""
Returns all the lists of primes that are permutations from one another,
of size 3 and that make an arithmetic suite.
"""
res = []
idx = 0
for prime in primes :
idx += 1
print "%d / %d" % (idx, len(primes))
perms = findPrimePerms(prime)
# gets all length 3 prime combinations
els = None
if perms > 2:
els = [list(x) for x in itertools.combinations(perms, 3)]
if els != None:
for primeList in els:
if isArithmetic(primeList):
res.append(primeList)
return res # removes duplicates
def isArithmetic(aList):
"""
Returns true if the list is arithmetic.
Elements of the list are expected to be numbers.
"""
diffs = [a - b for a, b in zip(aList[1:], aList[:-1])]
res = list(set(diffs)) # removes duplicates
return (len(res) == 1)
def findPrimePerms(prime):
"""
Returns all the list of primes that are permutations from prime
"""
perms = [int(val) for val in all_permutations(str(prime)) if (isPrime(int(val)) and len(str(int(val))) == 4)]
res = list(set(perms)) # removes duplicates
if len(res) > 2:
return res
if __name__ == '__main__':
primes = fourLengthPrime()
print getPrimesPermutations(primes, 3)
#itertools.combinations(lst, i)]
#getPrimesPermutations(primes, 3)
# try:
# while primes.next():
# print primes.next()
# except StopIteration:
# print "Reached end of list"
#print "Answer : %d " % (last_ten())