Files
project_euler/e_58.py
Julien Lengrand-Lambert d6a04fbe42 Solves problem 59
2014-05-25 11:39:57 +02:00

31 lines
965 B
Python

#!/usr/bin/env python
'''
Created on 10 feb. 2012
@author: Julien Lengrand-Lambert
DESCRIPTION: Solves problem 58 of Project Euler
Starting with 1 and spiralling anticlockwise in the following way,
a square spiral with side length 7 is formed.
37 36 35 34 33 32 31
38 17 16 15 14 13 30
39 18 5 4 3 12 29
40 19 6 1 2 11 28
41 20 7 8 9 10 27
42 21 22 23 24 25 26
43 44 45 46 47 48 49
It is interesting to note that the odd squares lie along the bottom right diagonal,
but what is more interesting is that 8 out of the 13 numbers lying along both
diagonals are prime; that is, a ratio of 8/13 ≈ 62%.
If one complete new layer is wrapped around the spiral above, a square spiral
with side length 9 will be formed. If this process is continued,
what is the side length of the square spiral for which the ratio of primes
along both diagonals first falls below 10%?
'''
if __name__ == '__main__':
print "plouf"
#print "Answer : %d " % (last_ten())