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project_euler/e_41.py
2012-10-16 19:29:39 +02:00

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2.6 KiB
Python

#!/usr/bin/env python
'''
Created on 10 feb. 2012
@author: Julien Lengrand-Lambert
DESCRIPTION: Solves problem 41 of Project Euler
We shall say that an n-digit number is pandigital if it makes use of all the digits 1 to n exactly once. For example, 2143 is a 4-digit pandigital and is also prime.
What is the largest n-digit pandigital prime that exists?
'''
val = 123456789 # all numbers to create the biggest pandigital number
def is_prime(value):
"""
Returns True or False depending whether value is prime or not.
"""
start = 2
while (start <= value / 2):
if value % start == 0 :
return False
else :
start += 1
return True
# I could use a decorator to remove trivial non primes here
def all_permutations(seq):
"""permutates a sequence and returns a list of the permutations"""
if not seq:
return [seq] # is an empty sequence
else:
temp = []
for k in range(len(seq)):
part = seq[:k] + seq[k+1:]
for m in all_permutations(part):
temp.append(seq[k:k+1] + m)
return temp
def divisible_by_2(val):
"""
Returns True if val contains an even number (ex : 998)
"""
return ((val % 2) == 0)
def divisible_by_5(val):
"""
Returns True if any circular permutation of val is divisible by (ex : 907)
"""
return (str(5) == str(val)[-1])
def divisible_by_3(val):
"""
Returns True if any circular permutation of val is divisible by 3 (ex : 12)
"""
temp = sum([int(p) for p in str(val)])
if len(str(temp)) > 1:
divisible_by_3(temp)
else:
return ((temp % 3) == 0)
def check_easy_out(pelist):
"""
Returns the number of circular primes below max_val
TODO : do this while creating all the permutations !
"""
pred = list(pelist)
for p in pelist:
if p > 11: # my filter does not work for values under 10
if (divisible_by_2(p) or divisible_by_5(p) or divisible_by_3(p)):
pred.remove(p)
return pred
def biggest_pandigital():
"""
Returns the biggest pandigital prime number
"""
for n in range(9): # from 0 to 9 numbers removed of max pand number
print " n : %d" %(n)
root = str(val)[:len(str(val)) -n]
perms = [ int(p) for p in all_permutations(root)]
perms = check_easy_out(perms)
perms.sort(reverse=True)
for p in perms :
if is_prime(p):
return p
return -1 # problem
if __name__ == '__main__':
print "Answer : %d " % (biggest_pandigital())