Files
kotlin/compiler/testData/codegen/bytecodeText/forLoop/unsigned/reversedThenStep.kt
2020-05-13 13:54:35 +02:00

43 lines
1.2 KiB
Kotlin
Vendored

// TARGET_BACKEND: JVM_IR
// WITH_RUNTIME
fun box(): String {
for (i in (1u..8u).reversed() step 2) {
}
return "OK"
}
// For "step" progressions in JVM IR, a call to getProgressionLastElement() is made to compute the "last" value.
// If the step is non-constant, there is a check that it is > 0, and if not, an IllegalArgumentException is thrown. However, when the
// step is constant and > 0, this check does not need to be added.
//
// Expected lowered form of loop:
//
// // Standard form of loop over progression
// val last = getProgressionLastElement(8u, 1u, -2)
// var inductionVar = 8u
// val step = -2
// if (last <= inductionVar) {
// // Loop is not empty
// do {
// val i = inductionVar
// inductionVar += step
// // Loop body
// } while (i != last)
// }
//
// We can't use "0 reversed" in the regex below because "reversed" is in the test filename.
// 0 INVOKE.*reversed
// 0 iterator
// 0 getStart
// 0 getEnd
// 0 getFirst
// 0 getLast
// 0 getStep
// 1 INVOKESTATIC kotlin/internal/UProgressionUtilKt.getProgressionLastElement
// 0 NEW java/lang/IllegalArgumentException
// 0 ATHROW
// 1 IFGT
// 1 IF_ICMPNE
// 2 IF