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506941e7e0
NB: for-in-until loop is generated as precondition loop, because the corresponding range is right-exclusive (and thus we have no problems with integer overflows).
18 lines
693 B
Kotlin
Vendored
18 lines
693 B
Kotlin
Vendored
fun Int.until(other: Int) = this..other - 1
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fun foo() {
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val range = 1 until 2
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for (i in range) {
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}
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for (i in 1..2 step 4) {}
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}
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// 1 INVOKEVIRTUAL kotlin/ranges/IntRange.getFirst \(\)I
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// 0 INVOKEVIRTUAL kotlin/ranges/IntRange.getFirst \(\)Ljava/lang/Integer;
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// 1 INVOKEVIRTUAL kotlin/ranges/IntRange.getLast \(\)I
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// 0 INVOKEVIRTUAL kotlin/ranges/IntRange.getLast \(\)Ljava/lang/Integer;
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// 1 INVOKEVIRTUAL kotlin/ranges/IntProgression.getFirst \(\)I
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// 0 INVOKEVIRTUAL kotlin/ranges/IntProgression.getFirst \(\)Ljava/lang/Integer;
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// 1 INVOKEVIRTUAL kotlin/ranges/IntProgression.getLast \(\)I
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// 0 INVOKEVIRTUAL kotlin/ranges/IntProgression.getLast \(\)Ljava/lang/Integer; |