Files
kotlin/compiler/testData/codegen/boxInline/defaultValues/lambdaInlining
Mikhael Bogdanov 6bf70a5dd2 Properly find invoke method on default lambda inlining
In general case parameter type could differ from actual default lambda type.
  E.g.: fun inlineFun(s: (Child) -> Base = { a: Base -> a as Child}),
  where type of default lambda is '(Base) -> Child'.
  In such case we should find somehow actual invoke method in bytecode knowing
  only name, number of parameters and that's actual invoke is non-synthetic
  regardless of bridge one.

  #KT-21946 Fixed
2019-01-02 12:37:06 +01:00
..
2018-08-31 15:34:18 +03:00
2018-06-28 12:26:41 +02:00
2018-08-15 18:20:07 +03:00
2018-06-28 12:26:41 +02:00