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In code like 'a?.b == 42', we can immediately generate equality comparison result when receiver is null (false for '==', true for '!='), since the primitive value is definitely non-null. Otherwise unnecessary boxing/unboxing is generated to handle possibly null result of 'a?.b'.
24 lines
523 B
Kotlin
Vendored
24 lines
523 B
Kotlin
Vendored
fun Long.id() = this
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fun String.drop2() = if (length >= 2) subSequence(2, length) else null
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fun doSimple1(s: String?) = s?.length == 3
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fun doLongReceiver1(x: Long) = x?.id() == 3L
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fun doChain1(s: String?) = s?.drop2()?.length == 1
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fun doIf1(s: String?) =
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if (s?.length == 1) "A" else "B"
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fun doSimple2(s: String?) = 3 == s?.length
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fun doLongReceiver2(x: Long) = 3L == x?.id()
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fun doChain2(s: String?) = 1 == s?.drop2()?.length
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fun doIf2(s: String?) =
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if (1 == s?.length) "A" else "B"
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// 0 valueOf
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