Files
kotlin/compiler/testData/codegen/boxMultiFile/accessorForProtectedInvokeVirtual/1.kt
Alexander Udalov 3c4b2994a9 Fix protected call to super method from lambda
Previously JVM back-end had an assumption that if we're calling a method
declared in the super class from a lambda via a synthetic accessor, that should
be a super call and it must be done with 'invokespecial'. Which is wrong
because a method declared in the super class may be open and overridden in the
subclass, so 'invokevirtual' should be used. Surprisingly, Java SE verifier
allowed both instructions, but on Android only the latter is possible

 #KT-8899 Fixed
 #KT-9052 Fixed
2015-09-08 20:28:35 +03:00

50 lines
1.1 KiB
Kotlin
Vendored

import test.A
import kotlin.test.assertEquals
open class B : A() {
fun box(): String {
val overriddenMethod: () -> String = {
method()
}
assertEquals("C.method", overriddenMethod())
val superMethod: () -> String = {
super.method()
}
assertEquals("A.method", superMethod())
val overriddenPropertyGetter: () -> String = {
property
}
assertEquals("C.property", overriddenPropertyGetter())
val superPropertyGetter: () -> String = {
super.property
}
assertEquals("A.property", superPropertyGetter())
val overriddenPropertySetter: () -> Unit = {
property = ""
}
overriddenPropertySetter()
val superPropertySetter: () -> Unit = {
super.property = ""
}
superPropertySetter()
assertEquals("C.property;A.property;", state)
return "OK"
}
}
class C : B() {
override fun method() = "C.method"
override var property: String
get() = "C.property"
set(value) { state += "C.property;" }
}
fun box() = C().box()