Files
kotlin/compiler/testData/codegen/bytecodeText/forLoop/stepped/stepThenStepNonConst.kt
2019-10-28 15:26:38 +01:00

50 lines
1.4 KiB
Kotlin
Vendored

// TARGET_BACKEND: JVM_IR
fun one() = 1
fun box(): String {
for (i in 1..6 step one() step one()) {
}
return "OK"
}
// For "step" progressions in JVM IR, if the step is non-constant, there is a check that it is > 0, and if not, an IllegalArgumentException
// is thrown.
//
// Expected lowered form of loop:
//
// // Additional variables:
// val innerStepArg = one()
// val innerNewStep = if (innerStepArg > 0) innerStepArg
// else throw IllegalArgumentException("Step must be positive, was: $innerStepArg.")
// val outerNestedLast = getProgressionLastElement(1, 6, innerNewStep)
// val outerStepArg = one()
// val outerNewStep = if (outerStepArg > 0) outerStepArg
// else throw IllegalArgumentException("Step must be positive, was: $outerStepArg.")
//
// // Standard form of loop over progression
// var inductionVar = 1
// val last = getProgressionLastElement(1, outerNestedLast, outerNewStep)
// val step = outerNewStep
// if (inductionVar <= last) {
// // Loop is not empty
// do {
// val i = inductionVar
// inductionVar += step
// // Loop body
// } while (i != last)
// }
// 0 iterator
// 0 getStart
// 0 getEnd
// 0 getFirst
// 0 getLast
// 0 getStep
// 2 INVOKESTATIC kotlin/internal/ProgressionUtilKt.getProgressionLastElement
// 2 NEW java/lang/IllegalArgumentException
// 2 ATHROW
// 1 IF_ICMPGT
// 1 IF_ICMPNE
// 2 IFLE
// 4 IF